设f(x)=cos2x+sinx 求f(π/3)的值
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设f(x)=cos2x+sinx 求f(π/3)的值
设f(x)=cos2x+sinx 求f(π/3)的值
设f(x)=cos2x+sinx 求f(π/3)的值
f(π/3)=cos(2π/3)+sin(π/3)=-cos(π/3)+sin(π/3)=-1/2+(根号3)/2
f(π/3)=cos(2π/3)+sin(π/3)=-cos(π/3)+sin(π/3)=-1/2+(根号3)/2
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