log(2x – 3)(x2-3)>0求解
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log(2x – 3)(x2-3)>0求解
log(2x – 3)(x2-3)>0
求解
log(2x – 3)(x2-3)>0求解
log(2x-3)(x²-3)>log(2x-3) (1)
若0<2x-3<1
3/2
所以0
x>2
则log是增函数
所以x²-3>1
x²>4
x<-2,x>2
所以x>2
所以
√3
log(2x – 3)(x2-3)>0
(2x-3-1)(x²-3-1)>0
∴(2x-4)(x²-4)>0
∴2(x-2)²(x+2)>0
∵2x-3>0,x²-3>0
∴x>√3
∴2(x-2)²(x+2)>0恒成立
∴x>√3
解log(2x – 3)(x2-3)>0 (2x-3)是底数.
log(2x – 3)(x2-3)>0求解
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