设函数f(x)=sinx+sin(x+π/3)(1)求f(x)的最小值,并求使f(x)取得最小值的x的集合(2)不画图,说明函数f(x)的图象可由y=sinx的图象经过怎样的变化得到

设函数f(x)=sinx,则[f（π/2)]' 设0 ≤ x≤π/2,函数f(x)=sin(cosx),g(x)=cos(sinx),比较f(x)和g(X)的大小 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=2sinx*cos方¤/2+cosx*sin¤(0 已知函数f(x)=sin(x-π/3)+根号3cos(x-π/3)求函数y=f(x)-1的单调递增区间，设函数g(x)=(1+sinx)f(X).求g(x)的值域 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2